How to calculate voltage drop over and power loss in wires
How do I calculate the voltage drop over wires given a supply voltage and a current? How do I anticipate on voltage drop so that the final load has the correct supply voltage? What will be
How do I calculate the voltage drop over wires given a supply voltage and a current? How do I anticipate on voltage drop so that the final load has the correct supply voltage? What will be
6 It''s not the voltage but the current that kills, is a popular yet still incorrect incomplete answer. It is the ENERGY that kills. With static electricity you will will be exposed to voltages much,
The total voltage you get from one out and back, even with a high temperature difference is pretty small. By putting many of these out and back combinations together, you can get a useful
Voltage instead "regulates" how fast a motor can run: the maximum speed a motor can reach is the speed at which the motor generates a voltage (named "Counter-electromotive
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And also if voltage is like gravitational potential energy, how does more voltage mean more current? And here our nice analogy breaks down. In this sense voltage is more
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According to Ohm''s law, resistance varies directly with voltage You should read this the other way. Voltage varies directly with current. "R" is the constant of proportionality telling how much
If power is a constant, then, yes, current and voltage are inversely proportional since power is their product. Again, this has nothing to do with Ohm''s Law. Ohm''s law says that voltage and
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An intuitive way to look at is that all the voltage is dropped across two resistors, and since the resistors are the same, the voltage drop across each will be the same, each taking half.
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